Reverse Compose: Difference between revisions
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</syntaxhighlight>{{Works in|[[dzaima/APL]], [[Extended Dyalog APL]]}} | </syntaxhighlight>{{Works in|[[dzaima/APL]], [[Extended Dyalog APL]]}} | ||
== External links == | == External links == | ||
=== Documentation === | |||
* [https://mlochbaum.github.io/BQN/doc/hook.html BQN] (as <code>⊸</code>) | |||
=== Publications === | |||
* [https://github.com/abrudz/primitives/blob/main/behind.aplf APL model] | * [https://github.com/abrudz/primitives/blob/main/behind.aplf APL model] | ||
== References == | == References == | ||
<references/> | <references/> | ||
{{APL built-ins}}[[Category:Primitive operators]][[Category:Composition operators]] | {{APL built-ins}}[[Category:Primitive operators]][[Category:Composition operators]] |
Revision as of 09:54, 13 October 2022
⍛
|
Reverse Compose (⍛
) is a primitive operator closely related to Beside (∘
), which appears in Extended Dyalog APL and dzaima/APL. Called dyadically with function operands f
and g
, it uses f
monadically to pre-processes the left argument before applying g
between the pre-processed left argument and the given right argument. X f⍛g Y
is thus equivalent to (f X) g Y
. The operator can be defined as the dop {(⍺⍺ ⍺) ⍵⍵ ⍵}
. This dyadic definition matches the hook function Before, represented as ⊸
in BQN.
Unlike Before, the monadic case of Reverse Compose has differed across implementations. When introduced by Extended Dyalog APL, f⍛g Y
evaluated to g Y
, but Brudzewsky's later Dyalog APL Vision defines[1] it to be Y f g Y
, matching Before. This later definition might also be written f⍛g
f⍛g⍨⍨
g⍨∘f⍨
. In dzaima/APL the monadic case is simply an error.
Common usage
Its plain usage is to pre-process left arguments without needing one or more applications of Commute (⍨
). For example, the square of the left argument minus the right argument can be expressed as:
3×⍨⍛-2 7
It can also be combined with Beside to create the split-compose construct. Here, we take the sign of the left argument and apply it to (that is, multiply it with) the absolute value of the right argument:
3 ¯1 4×⍛×∘|¯2 ¯7 1 2 ¯7 1
External links
Documentation
- BQN (as
⊸
)