Rule 110: Difference between revisions

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(An implementation and explanation of rule 110)
 
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Rule 110 is so-called because the binary number 01101110 is 110 in binary.
Rule 110 is so-called because the binary number 01101110 is 110 in decimal.


== Implementation ==
== Implementation ==
Since we will be using binary numbers to index arrays, it is more convenient for us to have arrays start at 0.
Since we will be using binary numbers to index arrays, it is more convenient for us to have arrays start at 0.
<source lang="apl">
<syntaxhighlight lang="apl">
⎕IO←0
⎕IO←0
</source>
</syntaxhighlight>


The lookup table can be created by simply converting the decimal number 110 into binary and flipping it.
The lookup table can be created by simply converting the decimal number 110 into binary and flipping it.


<source lang="apl">
<syntaxhighlight lang="apl">
⌽110⊤⍨8⍴2
⌽110⊤⍨8⍴2
</source>
</syntaxhighlight>


A function that takes the three cells as an argument can then easily be implemented by converting it into a decimal number and indexing that number in the table.
A function that takes the three cells as an argument can then easily be implemented by converting it into a decimal number and indexing that number in the table.
<source lang="apl">
<syntaxhighlight lang="apl">
{(2⊥⍵)⌷⌽110⊤⍨8⍴2}
{(2⊥⍵)⌷⌽110⊤⍨8⍴2}
</source>
</syntaxhighlight>


<source lang="apl">
<syntaxhighlight lang="apl">
       {(2⊥⍵)⌷⌽110⊤⍨8⍴2}0 0 0
       {(2⊥⍵)⌷⌽110⊤⍨8⍴2}0 0 0
0
0
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0
0
       etc...
       etc...
</source>
</syntaxhighlight>


But how are we going to iterate over an entire board? Well, it would be useful to have a function that would generate us a board first.
But how are we going to iterate over an entire board? Well, it would be useful to have a function that would generate us a board first.
<source lang="apl">
<syntaxhighlight lang="apl">
board←{1,⍨⍵⍴0} ⍝ this function creates an array full of 0s with a 1 at the end.
board←{1,⍨⍵⍴0} ⍝ this function creates an array full of 0s with a 1 at the end.
</source>
</syntaxhighlight>


APL has an interesting function that lets you operate over a small window of your choice.
APL has an interesting function that lets you operate over a small window of your choice.
<source lang="apl">
<syntaxhighlight lang="apl">
       3 , /⍳10
       3 , /⍳10
┌─────┬─────┬─────┬─────┬─────┬─────┬─────┬─────┐
┌─────┬─────┬─────┬─────┬─────┬─────┬─────┬─────┐
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└─────┴─────┴─────┴─────┴─────┴─────┴─────┴─────┘
└─────┴─────┴─────┴─────┴─────┴─────┴─────┴─────┘
        
        
</source>
</syntaxhighlight>


Wait! Eureka! That is exactly what we want! A 3 cell sized window!
Wait! Eureka! That is exactly what we want! A 3 cell sized window!


<source lang="apl">
<syntaxhighlight lang="apl">
solve←{{(2⊥⍵)⌷⌽110⊤⍨8⍴2}¨3,/0,⍵,0}
solve←{{(2⊥⍵)⌷⌽110⊤⍨8⍴2}¨3,/0,⍵,0}
</source>
</syntaxhighlight>
I did gloss over an important step, which is to pad the array with a 0 on both sides. This is because any cell that exceeds the bounds is considered dead no matter what, so we need to tell this explicitly to APL.
I did gloss over an important step, which is to pad the array with a 0 on both sides. This is because any cell that exceeds the bounds is considered dead no matter what, so we need to tell this explicitly to APL.


Anyway, now we have a solve function that can calculate the next generation given an array of any size. Now all we need to do is implement a function that can give you generations.
Anyway, now we have a solve function that can calculate the next generation given an array of any size. Now all we need to do is implement a function that can give you a specific generation.
 
<syntaxhighlight lang="apl">
 
<source lang="apl">
gen←{(solve⍣⍵)⍺}
gen←{(solve⍣⍵)⍺}
</source>
</syntaxhighlight>
And the grand finale...
And the grand finale...


<source lang="apl">
<syntaxhighlight lang="apl">
(board 10)∘gen¨⍳10
(board 10)∘gen¨⍳10
┌─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┐
┌─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┬─────────────────────┐
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└─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┘
└─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┴─────────────────────┘
        
        
</source>
</syntaxhighlight>
It worked! kinda...
It worked! kinda...


It printed all of the generations on one line, which is still a solution but not at all pretty. Luckily, we can reshape the array to go down not across.
It printed all of the generations on one line, which is still a solution but not at all pretty. Luckily, we can reshape the array to go down not across.
<source lang="apl">
<syntaxhighlight lang="apl">
       10 1⍴(board 10)∘gen¨⍳10
       10 1⍴(board 10)∘gen¨⍳10
┌─────────────────────┐
┌─────────────────────┐
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│0 1 1 0 0 0 0 0 1 1 1│
│0 1 1 0 0 0 0 0 1 1 1│
└─────────────────────┘
└─────────────────────┘
</source>
</syntaxhighlight>


Let's put this all into one function...
Let's put this all into one function...
<source lang="apl">
<syntaxhighlight lang="apl">
rule110←{⍵ 1⍴(board ⍵)∘gen¨⍳⍵}
rule110←{⍵ 1⍴(board ⍵)∘gen¨⍳⍵}
</source>
</syntaxhighlight>


And just for fun, let's use * for a 1 and a space for a 0
And just for fun, let's use * for a 1 and a space for a 0


<source lang="apl">
<syntaxhighlight lang="apl">
       ↑{⍵⌷' *'}¨¨rule110 25 ⍝ "{⍵⌷' *'}" will only work with 0 index.
       ↑{⍵⌷' *'}¨¨rule110 25 ⍝ "{⍵⌷' *'}" will only work with 0 index.
                         *
                         *
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  *******    * ***    ** *
  *******    * ***    ** *
</source>
</syntaxhighlight>


Beautiful.
Beautiful.
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== Full solution ==
== Full solution ==
<source lang="apl">
<syntaxhighlight lang="apl">
⎕IO←0
⎕IO←0
solve←{{(2⊥⍵)⌷⌽110⊤⍨8⍴2}¨3,/0,⍵,0}
solve←{{(2⊥⍵)⌷⌽110⊤⍨8⍴2}¨3,/0,⍵,0}
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rule110←{⍵ 1⍴(board ⍵)∘gen¨⍳⍵}
rule110←{⍵ 1⍴(board ⍵)∘gen¨⍳⍵}
↑{⍵⌷' *'}¨¨rule110 25
↑{⍵⌷' *'}¨¨rule110 25
</source>
</syntaxhighlight>
 
[[Category:Examples]]

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