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<source lang=apl inline>¨</source> applies a function to each 1 of the argument elements, so it is on <kbd>APL</kbd>+<kbd>1</kbd>.<br> | <source lang=apl inline>¨</source> applies a function to each 1 of the argument elements, so it is on <kbd>APL</kbd>+<kbd>1</kbd>.<br> | ||
<source lang=apl inline>⌶</source> looks like a [[wikipedia:Roman numerals|Roman numeral]] 1, so it also lives on the <kbd>1</kbd>. | <source lang=apl inline>⌶</source> looks like a [[wikipedia:Roman numerals|Roman numeral]] 1, so it also lives on the <kbd>1</kbd>. | ||
<source lang=apl inline>¯</source>, <source lang=apl inline><</source>, <source lang=apl inline>≤</source>, <source lang=apl inline>=</source>, <source lang=apl inline>≥</source>, <source lang=apl inline>></source>, and <source lang=apl inline>≠</source> form a block. The number line 1–9 (because 0 on the far right) is split into two [[equal]] halves by <kbd>5</kbd> so that gives <source lang=apl inline>=</source>. <kbd>4</kbd> and <kbd>6</kbd> are slightly less and more, respectively, so they give <source lang=apl inline>≤</source> and <source lang=apl inline>≥</source>. <kbd>3</kbd> and <kbd>7</kbd> are much less and more, respectively, so they give <source lang=apl inline><</source> and <source lang=apl inline>></source>. Finally, <kbd>2</kbd> is so much less that it is negative, giving the negative sign <source lang=apl inline>¯</source>, and <kbd>8</kbd> is so much greater that it is completely [[not equal|unequal]], <source lang=apl inline>≠</source>. | |||
{{APL development}}{{APL glyphs}} | {{APL development}}{{APL glyphs}} | ||
[[Category:APL character set]] | [[Category:APL character set]] |