FindRowsInMatrix

Returns an integer vector reporting how many times each row in AM1 is found in AM2:

      +/AM1^.=⍉AM2

Every row in AM1 is supposed to be unique. The number of columns in both matrices must be the same.

Examples

Add proper examples here, and don't forget to fix a sample function changing "PhraseName" accordingly

      ⎕FX ⍕2 1⍴'r←AM1 FindRowsInMatrix AM2' 'r←+/AM1^.=⍉AM2' 
      AM1←⊃'Barak Obama' 'George Bush' 'Bill Clinton' 'Ronald Reagan' 'Gerald Ford' 'John Kennedy'
      AM2←AM1[2 2 5;]
      AM1 FindRowsInMatrix AM2
0 0 2 0 0 1

Compatibility

Checked with: APLX, NARS2000, Dyalog APL2, APLX, APL+Win, Dyalog, NARS2000 - Add as many as you can/like

Remarks

You might want to make sure that a vector provided as right argument is automatically turned into a matrix. You can do so by making use of the phrase EnforceMatrix.

Test Cases

Replace "PhraseName" accordingly Show Hide test cases test cases

Test
 ⎕IO←0      ⍝ You may change this; however, zero IS the default in the Phrasebook
⍝⎕ML←3      ⍝ Enable this line in Dyalog APL if appropriate
  ⎕FX ⍕2 1⍴'r←AM1 FindRowsInMatrix AM2' 'r←+/AM1^.=⍉AM2'    ⍝ This will work in any APL dialect
⍝ ---- Start Test cases (do not delete this!)
1 0 0 1 ≡ (⊃'Barak Obama' 'George Bush' 'Bill Clinton' 'Ronald Reagan') FindRowsInMatrix  ⊃'Ronald Reagan' 'Barak Obama'
0 1 0 2 ≡ (⊃'Barak Obama' 'George Bush' 'Bill Clinton' 'Ronald Reagan') FindRowsInMatrix ⊃'Ronald Reagan' 'George Bush' 'Ronald Reagan'
⍬≡(0 13⍴' ') FindRowsInMatrix ,[-.5]'Ronald Reagan'
0 0 0 3 0 0≡(⊃6/¨⍳6) FindRowsInMatrix ⊃3⍴⊂6/3 
0 0 0 0 0 0≡      (⊃6/¨⍳6) FindRowsInMatrix ,[-.5],7

Test my code, both Examples and Test Cases.

See also: FindRowInMatrix

Mentor: KaiJaeger

CategoryPhrasesAll CategoryPhraseSelection